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Solve 2^x=32 and rewrite this equation in a logarithmic form.

I have an answer for it, if someone wants to check it pls!

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Respuesta :

iiKajanaii

[tex] {2}^{x} = 32 \\ log( {2}^{x} ) = log(32) \\ xlog2 = log(32) \\ x = \frac{ log(32) }{2} \\ x = 5[/tex]

Answer:

log2 32 = x

Step-by-step explanation:

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