ethanhigginb ethanhigginb
  • 24-05-2018
  • Mathematics
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gmany
gmany gmany
  • 05-07-2018
[tex]7\dfrac{2}{9}-3\dfrac{5}{6}=7\dfrac{2\cdot2}{9\cdot2}-3\dfrac{5\cdot3}{6\cdot3}=7\dfrac{4}{18}-3\dfrac{15}{18}\\\\=6\dfrac{22}{18}-3\dfrac{15}{18}=3\dfrac{7}{18}[/tex]
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