Each of the triangles making up the sides and base have a base of 8 cm and a height of 6.9 cm. Then the area of the pyramid is that of 4 such triangles. A = 4×(1/2)×b×h A = 2×(8 cm)×(6.9 cm) A = 110.4 cm²
The surface area of the triangular pyramid is 110.4 cm².
What we must do is observe that the triangles have the same measurements. We have then that the surface area is: A = (4) * (1/2) * (b) * (h) Where, b: base of the triangle h: height of the triangle Substituting values: A = (4) * (1/2) * (8) * (6.9) A = 110.4 cm ^ 2 Answer: The surface area of the triangular pyramid is: A = 110.4 cm ^ 2
