Answer:- d. -0.35 degree C is the right answer.
Solution:- depression in freezing point, delta Tf formula is...
delta Tf = i x m x kf
where, i is Van't hoff factor. glucose is covalent compound and does not dissociate to give ions and so the value of i for this is 1.
m is molaity and kf is the molal freezing point constant.
Let's plug in the given values in the formula..
delta Tf = 1 x 0.19 x 1.858
delta Tf = 0.35
Pure water freezes at 0 degree C.
So, freezing point of solution = 0 - 0.35 = -0.35 degree C
