Answer:
2x/(x+3) +3/(x-3) = 8/(x^2
[2x(x-3) +3(x+3)]\( x^2 - 9) =8/(x^2 -9)
2x^2 -6x +3x +9=8 (x^2 -9) /(x^2 -9)
2 x^2 -3x +9 -8=0
2 x^2 -3x +1 =0
2x^2 -2x -1x +1 =0
2x(x-1) -1(x-1)=0
(x-1)(2x-1)=0
either, or, 2x-1=0
x-1 =0 2x =1
x =1 x= 1/2
hence, x= 1, 1/2
