Answer:
r=5
Step-by-step explanation:
[tex]\theta=\frac{2\pi }{3}\\l=\frac{10\pi }{3}\\\theta=\frac{l}{r}\\r=\frac{l}{\theta } \\r=\frac{\frac{10 \pi }{3} }{\frac{2\pi }{3} } \\or~r=\frac{10\pi }{3} *\frac{3}{2\pi } =5[/tex]
