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Perform the operation indicated, then place the answer in the proper location on the grid. Write your answer in descending powers of a.

By how much does a 3 - 2a exceed a 2 + a - 6?

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Respuesta :

eternal3fear
First we should find out
"how much does a^3 - 2a exceed a^2 + a - 6 ?"

this would be
(a^3 - 2a) - (a^2 + a - 6)

we distribute the negative
a^3 - 2a - a^2 - a + 6

a^3 - a^2 - 3a + 6
(I made it already decending in powers out of habit, note that it is a^3 followed by a^2 then a etc)

therefore a^3 - a^2 - 3a + 6 would be your answer

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