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A 35.0-9 piece of copper wire is heated, and the temperature of the wire changes from 29.0°C to 76.0 degrees * C . The amount of heat absorbed is 243 cal. What is the specific heat of copper?

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Answer:

c = 0.1477 cal/g·°C

Explanation:

q = mcΔT => c = q/mΔT = 243cal/(35.0 g)(76°C-29°C) = 0.1477 cal/g·°C

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