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ABCD, EFGH, and HIJK are squares.
AABCD = 400 cm2, O is the center of the circle, O ∈
FE
,
FG
and
BC
tangent to the circle (see the picture on the right).

Find the length of
AM
.

ABCD EFGH and HIJK are squares AABCD 400 cm2 O is the center of the circle O FE FG and BC tangent to the circle see the picture on the right Find the length of class=
Relax

Respuesta :

amna04352

Answer:

40/3 cm

Step-by-step explanation:

FE : DC

1 : 3

Since area ABCD = 400

s² = 400

s = 20

FE = ⅓(20) = 20/3 cm

AM = DC - FE

AM = 20 - 20/3 = 40/3

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