Answer:
The resistance is [tex]R = 2.88 \ \Omega[/tex]
Explanation:
From the question we are told that
The voltage rating of the headlamp is [tex]V_1 = 12 \ V[/tex]
The voltage of the power system is [tex]p = 24 \ V[/tex]
The power rating of the headlamp is [tex]P = 50 W[/tex]
Generally the power which the resistor dissipates is mathematically represented as
[tex]P = V_L * I[/tex]
=> [tex]50 = 12 * I[/tex]
=> [tex]I = 4.1667 \ A[/tex]
Generally the resistance is
[tex]R = \frac{V_1 }{I}[/tex]
[tex]R = \frac{12 }{4.1667}[/tex]
[tex]R = 2.88 \ \Omega[/tex]
