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Find three consecutive odd integers such that the sum of the smallest number and twice the largest number is equal to fifteen more than four times the middle number.

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Answer:

The three consecutive odd integers are: -11, -13 and -15.

Step-by-step explanation:

Let the smallest number be represented by x. then the three consecutive odd integers are: x, (x + 2) and (x = 4).

The sum of the smallest number and twice the larges number = x + 2(x + 4)

Fifteen more than four times the middle number = 4(x + 2) + 15

So that;

x + 2(x + 4) = 4(x + 2) + 15

x + 2x + 8 = 4x + 8 + 15

3x + 8 = 4x + 23

3x - 4x = 23 - 8

-1x = 15

⇒ x = -15

  (x + 2) = (-15 + 2) = -13

  (x + 4) = (-15 + 4) = -11

The three consecutive odd integers are: -11, -13 and -15.

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