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∠A and \angle B∠B are complementary angles. If m\angle A=(4x-28)^{\circ}∠A=(4x−28)
∘
and m\angle B=(x-2)^{\circ}∠B=(x−2)
∘
, then find the measure of \angle A∠A

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Answer:

∠A = 26°

Step-by-step explanation:

Supplementary angles total 180°.

 ∠A +∠B = 180°

 (x -16)° +(3x +28)° = 180°

 4x° + 12° = 180°

 x° +3° = 45°

 x° = 42°

 ∠A = (x -16)° = 42° -16°

 ∠A = 26°

brainliest please?

kadenmoline

Answer:

68 not 26

Step-by-step explanation:

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