The school zone in front of your school has a posted speed limit of 25mi/h which is about 11 m/s. Let’s examine the stopping of car is several different situations. The crossing guard holds up her stop sign, and the driver is paying attention as well. The car moves at a constant velocity of 11 m/s for 2.3 second while the driver reacts, then slows down at a constant rate or -4.5 m/s. What is the stopping distance for the car in this situation?

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Answer:

x=13.4

Step-by-step explanation:

x=v_i(t)+1/2(at^2 )

x=11(23)+12(-4.5)(2.3)^2

x=25.3-11.9

x=13.4