xvxbrenda
xvxbrenda xvxbrenda
  • 21-12-2020
  • Mathematics
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CSMedrano
CSMedrano CSMedrano
  • 21-12-2020

Answer:

[tex]h(x)=\frac{1}{5}x[/tex]

Step-by-step explanation:

[tex]6x+y=4x+11y\\\\6x-4x=11y-y\\\\2x=10y\\\\y=\frac{2x}{10}\\\\y=\frac{1}{5}x[/tex]

so h(x) is

[tex]h(x)=\frac{1}{5}x[/tex]

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