24-12-2020
Mathematics

contestada

sum of the series:
13, 16, 19, ..., 301
how many numbers are in this series?

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Respuesta :

surjithayer10 surjithayer10

24-12-2020

Answer:

97

Step-by-step explanation:

13,16,19,...,301

a=13

d=16-13=3

l=a+(n-1)d

301=13+(n-1)3

301-13=(n-1)3

(n-1)3=288

n-1=288/3=96

n=96+1=97

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paytonrcharles paytonrcharles

24-12-2020

Answer:

92

Step-by-step explanation:

Answer Link

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