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22-01-2021
Physics

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A spring with a spring constant of 200 N/m stretches by 0.03 m. What is the potential energy of the spring?

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isaiahyanez2004 isaiahyanez2004

26-01-2021

Answer: 0.09 J

Explanation: K = 200 N/m , 1/2 X 200 N/m X (0.03 M)^2 = 0.09 J

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