A person walks first at constant speed of 5.00 m/s along a straight line from point A to point B and then back along the line from B to A at a constant speed of 3.00 m/s. What is her average speed over the entire trip?

Relax

Respuesta :

As one distance is including twice, we can use the formula, 
S = 2s1s2 / s1+s2
S = 2*3*5 / 3+5
S = 30 / 8
S= 3.75 m/s

So, your final answer is 3.75 m/s

Hope this helps!