stuart40 stuart40
  • 25-11-2021
  • Mathematics
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Hello how do you solve 5^-x = 6?

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mathstudent55
mathstudent55 mathstudent55
  • 25-11-2021

Answer:

x = -log 6/log 5

Step-by-step explanation:

When the variable is in te exponent, logarithms help solve the equation very often.

5^-x = 6

Take the log of both sides.

log (5^-x) = log 6

Use the law of log of a power.

-x log 5 = log 6

-x = log 6/log 5

x = -log 6/log 5

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