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Given the function () = $% ) − 3 + 5, determine the inverse relation.

Determine the sum of the arithmetic series 5 + 18 + 31 + 44 + ... 161

If the 11th term of a geometric sequence is 32 times larger than the 6th term, then
what is the common ratio of the sequence?

I need your help ASAP Given the function 3 5 determine the inverse relation Determine the sum of the arithmetic series 5 18 31 44 161 If the 11th term of a geom class=
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The common ratio of the geometric sequence is 2

What is a series?

The term series has to do with an addition of figures. We can see that the series is give as  5 + 18 + 31 + 44 + ... 161. The sum of the series can be obtained by the use of the formula;

Sn = n/2(a + l)

n = number of terms

a = first term

l = last term

Then;

Un = a + (n - 1) d

161 = 5 + (n - 1)13

161 = 5 + 13n - 13

161 -(5 +13) = 13n

143 = 13n

n = 11

Thus;

Sn = 11/2( 5 + 161)

Sn = 913

The sum of the arithmetic progression is 913.

Again

T11 = ar^10

T6 = ar^5

T11 = T6 + 32

ar^10 = ar^5 + 32

ar^10 - ar^5 = 32

ar^10/ar^5 = 32

r^5 = 32

r = 2

Hence, the common ratio  is 2.

Learn more about sequence and series:https://brainly.com/question/12429779

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