Respuesta :
Thought i answered this one already
a)
m∠2 = 180 - m∠1 - m∠3
m∠2 = 180 - 79 - 27
m∠2 = 74
b)
m∠4 = m3 = 27 (vertical angles)
c)
m∠6 = 180 - m∠4 -m∠5
m∠6 = 180 -27 - 82
m∠6 = 71
a)
m∠2 = 180 - m∠1 - m∠3
m∠2 = 180 - 79 - 27
m∠2 = 74
b)
m∠4 = m3 = 27 (vertical angles)
c)
m∠6 = 180 - m∠4 -m∠5
m∠6 = 180 -27 - 82
m∠6 = 71
-34.6 79 times 3 devided by m times 5 minus 82 I think im not sure if I am wrong them delete my awnser.
