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21-06-2017
Mathematics

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what is the length of the focal width x=-1/8y^2

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04-07-2017

The standard equation is 4p(x-h) = (y-k)^2 where |p| = focal distance |4p| = focal width.

x=-1/8y^2
-8x=y^2
4*(-2)(x-0) =( y-0)^2

p = -2, h=0, k=0

focal width = |4*(-2)| = 8

The answer to your question is that the length of the focal width is equal to 8.

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