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A 5 kg ball rolls toward a 4 kg ball initially at rest. After they collide, the 5 kg ball stops and the 4 kg ball rolls off. If the 5 kg ball was initially moving at 2.5 m/s, what was the velocity of the 4 kg ball after the collision

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2024ZhaA

Answer:

v = 3.125 m/s

Explanation:

If the 5 kg stops after they collide, that means that all of the energy that was in the ball was transfers to the 4kg ball. Thus, we can use the equation.

m1v1 = m2v2

substitute values

(5 kg)(2.5 m/s) = (4kg) (v2)

Solve for velocity

v = 3.125 m/s

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