the perimeter of a square is 20 ft. if you increase the length of the square by 2 feet and decrease the width by 1 foot what is the area, in square feet, of the new figure?
A square has four equal sides a, so the perimeter is 4a. [tex]4a=20 \\
a=\frac{20}{4} \\
a=5[/tex] The side of the square is 5 ft long.
The length is increased by 2 ft -> 5+2=7 ft. The width is decreased by 1 ft -> 5-1=4 ft.
The new figure is a rectangle with the dimensions 4 ft x 7 ft. The area of a rectangle is the product of the length and the width. [tex]A=4 \times 7=28[/tex]
