jblakes03
jblakes03
22-03-2018
Mathematics
contestada
Simplify the radical expression.
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Аноним
Аноним
22-03-2018
[tex]
\dfrac{ \sqrt{6}}{ \sqrt{2n} } \\ \\
= \dfrac{ \sqrt{3 \times 2}}{ \sqrt{2 \times n} } \\ \\
= \dfrac{ \sqrt{3} \times \sqrt{2} }{ \sqrt{2} \times \sqrt{n} } \\ \\
= \dfrac{ \sqrt{3} }{ \sqrt{n}} \\ \\
= \sqrt{ \dfrac{3}{n}}
[/tex]
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