The reaction between KOH and HBr is as follows ; KOH + HBr ---> H₂O + KBr Stoichiometry of base to acid is 1:1 molar ratio Both are strong acid and strong base therefore complete ionization takes place The number of KOH moles added - 0.50 M / 1000 mL/L x 22 mL = 0.011 mol the number of HBr moles - 0.25 M /1000 mL/L x 44 mL = 0.011 mol the number of H⁺ ions and OH⁻ ions are equal therefore the whole amount of acid has been completely neutralised by base. No remaining acid nor base, therefore solution is neutral. pH = 7 thats the pH value for a neutral solution
